The maximum height reached by the ball is 0.46m.
To find the answer, we have to know about the potential energy of a spring mass system.
[tex]k=400N/m\\m=1kg\\x=0.150m\\h=?\\[/tex]
[tex]U=\frac{1}{2}kx^2 \\U=mgh[/tex]
[tex]h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m[/tex]
Thus, we can conclude that, the maximum height reached by the ball is 0.46m.
Learn more about the potential energy here:
https://brainly.com/question/26962934
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