The magnitude of the force is(F)= 0 N.
To calculate the force here we use the formula,
[tex]F= I \times L \times B \times sin\theta[/tex]
Here we are given,
I= The current passing through the wire = 0.60A.
L= The length of the wire= 2.0 m.
B= The magnetic field created by the wire= 0.50T.
[tex]\theta[/tex]= The angle that the wire makes after orientation= 0° (because its orientation is parallel).
We have to find the magnitude of the force = F
Now, we substitute the known values in the above equation,
[tex]F= I \times L \times B \times sin\theta[/tex]
Or, [tex]F= 0.60 \times 2.0 \times 0.50 \times sin (0)[/tex]
Or, F=0
Now from the above calculation we can conclude that, the magnitude of force is 0 N.
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