Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.
It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.
It is defined as the ratio of number of moles of compound to the volume of compound.
Solute S has a partition coefficient of 5 between water and hexane
Partition coefficient Kd = 5.0
Now we calculate the concentration of S in hexane
[hexane]/[water] = Kd
[Hexane]= 5.0 × (water)
[Hexane] = 5 × (0. 011)
[Hexane] = 0.055 m
Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.
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