The initial ph of the 0. 10M ch3cooh (aq) solution is -0.64.
The salt sodium acetate is present at the equivalency point. It is a salt of a strong base and a weak acid. The expression "its pH" provides the information.
pH = 7 + 0.5p + 0.5logC
where C is the salt concentration. Monobasic acid is Acetic acid here.
25 ml of 0.10 M NaOH solution are needed for the titration of 25 ml of 0.10 M acetic acid.
Total volume = 25 + 25 = 50ml
The salt concentration = C = 0.10× = 0.05
The pH for weak acid is given by,
pH = [tex]\frac{1}{2}[/tex] (p[tex]K_{a}[/tex] + logC)
pH = [tex]\frac{1}{2}[/tex] (1.8× + log0.05)
pH = [tex]\frac{1}{2}[/tex] [1.8× + (-1.30)]
pH = [tex]\frac{1}{2}[/tex] (1.8× -1.30)
pH = -0.64
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