The lifetime of meson according to laboratory clocks would be 14 μs.
In this question,
Meson decay, Δt = 2μs
Velocity, y = 0.99C, where C is the speed of the light
Time measurement depends on the reference frame of clock.
Time dilation, Δt' = y Δt
⇒ [tex]\frac{\Delta t }{\sqrt{1-\frac{v^{2} }{c^{2} } } }[/tex]
⇒ [tex]\frac{2(10^{-6} ) }{\sqrt{1-\frac{(0.99c)^{2} }{c^{2} } } }[/tex]
⇒ [tex]\frac{2(10^{-6} ) }{\sqrt{1-0.99^{2} } } }[/tex]
⇒ [tex]\frac{2(10^{-6} ) }{\sqrt{1-0.9801 } } }[/tex]
⇒ [tex]\frac{2(10^{-6} ) }{\sqrt{0.0199} } }[/tex]
⇒ [tex]\frac{2(10^{-6} ) }{0.1410} } }[/tex]
⇒ 14.18 × 10⁻⁶ ≈ 14 μs
Hence we can conclude that the lifetime of meson according to laboratory clocks would be 14 μs.
Learn more about lifetime at laboratory clocks here
https://brainly.com/question/23455167
#SPJ4
