Match each quadratic function given in factored form with its equivalent standard form listed on the left. f(x) = (x 2)(x – 6) f(x) = (x – 4)(x 3) f(x) = (x – 12)(x 1) f(x) = (x – 3)(x 4)

Respuesta :

standard form of the given equation are

-f(*) = (x + 2)(x - 6) = x² - 4x - 12

f(x) = (x - 4)(x + 3) = x² - x - 12

f(x) = (x - 12)(x + 1) = x² - 11x - 12

f(x) = (x -3)(x + 4) = x² + x - 12

What is quadratic function?

A polynomial function with one or more variables in which the second-degree term is the highest degree is known as a quadratic function, quadratic polynomial, polynomial of degree 2, or simply a quadratic, in algebra.

What is standard form of a quadratic function?

As long as an is not equal to zero, the quadratic function f(x) = a(x - h)2 + k is considered to be in standard form. The graph starts out in either an upward or a downward direction depending on the value of a. The point at the vertex of the symmetry is represented by the vertical line x = h. (h,k).

According to the given information:

The standard form list.

1 .   (x + 2)(x - 6)

= x² - 6x + 2x - 12

=  x² - 4x -12

2.  (x - 4)(x + 3)

    = x² + 3x - 4x - 12

   =   x² - x - 12

3. (x - 12)(x + 1)

    = x² + 1x - 12x - 12

    =  x² - 11x - 12

4.  (x -3)(x + 4)

    =   x² + 4x - 3x - 12

     = x² + x - 12

So the equivalent standard form  of the give values are :

-f(*) = (x + 2)(x - 6) = x² - 4x - 12

f(x) = (x - 4)(x + 3) = x² - x - 12

f(x) = (x - 12)(x + 1) =  x² - 11x - 12

f(x) = (x -3)(x + 4) = x² + x - 12

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I understand that the question you are looking for is:

Match each quadratic function given in factored form

with its equivalent standard form listed on the left.

f(x) = (x + 2)(x – 6)

f(x) = (x – 4)(x+3)

f(x) = (x – 12)(x+1)

f(x) = (x – 3)(x +4)