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2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)


2.0 moles C6H6 reacts with oxygen according to the reaction above. What volume of water vapor forms at STP?

2C6H6g 15O2g 12CO2g 6H2Og20 moles C6H6 reacts with oxygen according to the reaction above What volume of water vapor forms at STP class=

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pstnonsonjoku

At STP, the volume of water that is produced is 134.4 L.

What is the volume?

Now we know that the equation of the reaction is;

2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)

We can use the stoichiometry of the reaction to determine the volume of the water produced as follows;

2 mole of C6H6 produced 6 moles of water. If 1 mole of water occupies 22.4 L then 6 moles of water will occupy 6 * 22.4 L = 134.4 L

Thus, we can see that at STP, the volume of water that is produced is 134.4 L.

Learn more about stoichiometry:https://brainly.com/question/9743981

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