a. Applying the angle of intersecting chord theorem, m∠AEB = 57°.
b. Applying the , angle of intersecting tangents or secants theorem, VW = 106°.
According to the angle of intersecting chord theorem, the angle formed inside a circle (i.e. angle AEB) by two chords (i.e. AC and BD) have a measure that is equal to half of the sum of the measures of intercepted arcs AB and CD.
According to the angle of intersecting tangents or secants theorem, the angle formed outside a circle (i.e. angle VZW) have a measure that is equal to half of the positive difference of the measures of intercepted arcs XY and VW.
a. m∠AEB = 1/2(measure of arc AB + measure of arc CD) [angle of intersecting chord theorem]
Substitute
m∠AEB = 1/2(53 + 61)
m∠AEB = 57°
b. 35 = 1/2(VW - 36) [angle of intersecting tangents or secants theorem]
Multiply both sides by 2
2(35) = VW - 36
70 = VW - 36
Add 36 to both sides
70 + 36 = VW
VW = 106°
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