3.74×[tex]10^{21}[/tex]
3.74 ×[tex]10^{21}[/tex] molecules of propane were in the erlenmeyer flask.
number of moles of propane can be calculated as moles of propane.
mass of propane = 0.274 g
molar mass of propane = 44.1
So this gives us the value of 6.21×[tex]10^{-3}[/tex] moles of propane
No one mole of propane As a 6.0-2 × [tex]10^{23}[/tex]
so, 6.21 ×[tex]10^{-3}[/tex] × 6. 022 × 10^23
= 3.74 ×[tex]10^{21}[/tex]
Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×[tex]10^{21}[/tex]
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