The true statements are;
Now we can see that the reaction here is a redox reaction. Thus;
Eocell = cell potential = 0.54 - (-0.41) = 0.95 V
K = equilibrium constant = ?
n = number of moles of electrons = 2
ΔG = change in free energy = ?
Hence;
Eocell = 0.0592/n log K
0.95 = 0.0592/2 log K
K = 0.95 * 2/0.0592
K = 1.2 * 10^32
Now
ΔG = -nFEcell
ΔG = - (2 * 96500 * 0.95)
ΔG = -183.3kJ
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