A string that is 0.250 m long has a bob with a mass of 12.3 kg placed on it. It is allowed to swing so that it's amplitude is 0.100 m. What is the period of oscillation?1.00 s0.160 s246s39.3 s

Respuesta :

The period of a pendulum is given by:

[tex]T=2\pi\sqrt{\frac{L}{g}}[/tex]

where L is the length of the sting and g is the acceleration of gravity. In this case the length of the string is 0.250 m, plugging the values we have:

[tex]\begin{gathered} T=2\pi\sqrt{\frac{0.250}{9.8}} \\ T=1.00 \end{gathered}[/tex]

Therefore, the period is 1.00 s