Respuesta :

Given:

[tex]f(t)=300(1-t)^5[/tex]

The exponential growth formula is,

[tex]\begin{gathered} y=a(1+r)^x \\ r=\text{ grwoth rate} \\ a=\text{ initial value} \\ x=\text{ time} \end{gathered}[/tex]

The exponential decay formula is,

[tex]\begin{gathered} y=a(1-r)^x \\ r=\text{ decay rate} \\ a=\text{ initial value} \\ x=\text{ time} \end{gathered}[/tex]

So, the given equation is exponential decay.

The starting value of the function is 300