Respuesta :
ANSWER:
0.5563 m
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 5.87 kg
Voltage (V) = 10 kV = 10000 V
Charge (q) = 3.2 mC = 3.2 x 10^-3 C
First, we calculate the kinetic energy, as follows:
[tex]\begin{gathered} KE=q\cdot V \\ \\ KE=3.2\cdot10^{-3}\cdot10000 \\ \\ KE=32\text{ N} \end{gathered}[/tex]This is the kinetic energy of the rocket when it comes out of the hole, it is equal to the potential energy, therefore we can calculate the maximum height to which the rocket rises as follows:
[tex]\begin{gathered} KE=PE \\ \\ PE=mgh \\ \\ \text{ we replacing:} \\ \\ 32=5.87\cdot9.8\cdot h \\ \\ h=\frac{32}{5.87\cdot9.8} \\ \\ h=0.5563\text{ m} \end{gathered}[/tex]The maximum height of the rocket is 0.5563 meters
