Answer:
x = -8 OR 16
Step-by-Step Explanation:
Given the equation:
[tex](x-4)^2=144[/tex]We want to find the value of x.
First of all, notice that the left-hand side is the square of the right-hand side, the square can be neutralized by taking the square roots of both sides. Doing this, we have:
[tex]\sqrt[]{(x-4)^2}\text{ = }\sqrt[\square]{144}[/tex]So, performing the operation above, we have:
[tex]x-4\text{ = }\pm12[/tex]We are going to have two possible solutions, which are:
[tex]x\text{ = 12 +4 = 16}[/tex]OR
[tex]x\text{ = -12+4 = -8}[/tex]Therefore the two possible solutions are:
x = -8 or x = 16
