Suppose that an ideal gas in a sealed metal container (so it has a fixed volume) has its temperature increased by a factor of 1.55x. By what factor would the pressure of the gas increase or decrease in the container?

Respuesta :

In order to find the factor that the pressure will decrease or increase, we need to analyse the following equation:

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

This equation means the relation PV/T is always constant, where P is the pressure, V is the volume and T is the temperature.

So, using the given information, we have:

[tex]\begin{gathered} \frac{P_1V}{T_1}=\frac{P_2V}{T_2}\\ \\ \frac{P_1}{T}=\frac{P_2}{1.55T}\\ \\ P_1=\frac{P_2}{1.55}\\ \\ P_2=1.55P_1 \end{gathered}[/tex]

That means the pressure will increase by 1.55x.