Answer:
The equation of the line with a slope of 3 that passes through (-4,-7) is;
[tex]y=3x+5[/tex]Explanation:
We want find the equation of the line with;
[tex]\begin{gathered} \text{Slope m}=3\text{ } \\ \text{ passing through point }(x_1,y_1)\rightarrow(-4,-7) \end{gathered}[/tex]Using the point slope form of linear equation;
[tex]y-y_1=m(x-x_1)[/tex]substituting the given values into the equation above we have;
[tex]\begin{gathered} y-(-7)=3(x-(-4)) \\ y+7=3(x+4) \end{gathered}[/tex]Above is a point slope form of the equation.
solving further we have;
[tex]\begin{gathered} y+7=3x+12 \\ y+7-7=3x+12-7 \\ y=3x+5 \end{gathered}[/tex]The equation of the line with a slope of 3 that passes through (-4,-7) is;
[tex]y=3x+5[/tex]