Answer:
[tex]3.75\text{ g}[/tex]Explanation:
Here, we want to calculate the mass that would dissolve
Mathematically:
[tex]\begin{gathered} mass\text{ = number of moles }\times\text{ molar mass} \\ \end{gathered}[/tex]The molar mass of carbon (iv) oxide is 44 g/mol
Thus, we have the number of moles as:
[tex]number\text{ of moles = }\frac{mass}{44}[/tex]According to Henry's law:
[tex]C\text{ = KP}[/tex]Where;
C is the concentration of dissolved gas
K is the Henry's constant
P is the pressure
Now, from the question, we have:
k = 3.2 * 10^-2
P = 2.75
C is the number of moles per liter which we will represent by the number of moles
Thus, we have it that:
[tex]\begin{gathered} \frac{mass}{44}\text{ = 3.10 }\times\text{ 10}^{-2}\text{ }\times2.75 \\ \\ mass\text{ = 3.75 g} \end{gathered}[/tex]