Given:
The height is, twice the base - 3, h = 2b - 3.
The area is, A = 27.
We have,
[tex]A=\frac{1}{2}bh[/tex]That is,
[tex]\begin{gathered} 27=\frac{1}{2}\times b\times(2b-3)_{} \\ 54=2b^2-3b \\ 2b^2-3b-54=0 \end{gathered}[/tex]Solving for b, we have,
[tex]b=6[/tex]therefore, height is,
[tex]2\times6-3=12-3=9[/tex]Thu, base = 6, height = 9
