Juan conducted a survey of 550 employees of a company about their favorite pastime. Of these, 169employees chose playing games, 233 employees chose swimming. Compare the probability of an employee'schoosing playing games to an employee's choosing swimming.O about 32% to about 44%O about 32% to about 42%O about 31% to about 42%O about 31 % to about 44%

Respuesta :

SOLUTION

Write out the given data from the question

[tex]\begin{gathered} \text{Total employees=550} \\ E\text{mployes playing games =169} \\ \text{Employees for swimming=233} \end{gathered}[/tex]

The probabilty of an event is given by the formula

[tex]\frac{\text{ Required outcome}}{Total\text{ outcome }}[/tex]

Let

The probabilty of Employing playing games be P(E)

The probabilty of Employing for swimming be P(F)

then

[tex]\begin{gathered} P(E)=\frac{\text{Number of employ}ees\text{ playing games}}{Total\text{ number of employ}ees} \\ \\ \end{gathered}[/tex]

Where

Number of employees playing games =169

Total employees =550

Substituting the values, we have

[tex]P(E)=\frac{169}{550}=0.3072[/tex]

Since the probability is in percentage, multiply by 100

[tex]P(E)=0.3072\times100=30.72[/tex]

Hence,

The probability of employees playing game at pastime is about 31%

Similarly,

[tex]\begin{gathered} P(F)=\frac{\text{Number of swimming employ}ees}{Total\text{ employe}es} \\ \text{Where } \\ \text{Number of swimming employ}ees=233 \\ Total\text{ employe}es=550 \end{gathered}[/tex]

Substituting the values, we have

[tex]P(F)=\frac{233}{500}=0.4236[/tex]

Since the probability is in percentages, We multiply by 100

Hence

[tex]P(F)=0.4236\times100=42.36[/tex]

Hence

The probabilty of the employes swimming at passtime is about 42%

Therefore

the probability of an employee's choosing playing games to an employee's choosing swimming is about 31% to about 42%

Answer; about 31% to about 42%(Third option)