The number of time 6 appears is 56 and total frequancy observation is,
[tex]19+24+35+38+18+56=190[/tex]The possibility for the 6 in 190 obsevations is,
[tex]P(x)=\frac{56}{190}[/tex]The possibility for 570 observations is,
[tex]\begin{gathered} X(6)=\frac{56}{190}\times570 \\ =168 \end{gathered}[/tex]So answer is 168.