Given:
Find:(a) Approximate width "w" of house.
(B) Approximate Height of roof.
Sol:.
(a) Use Pythagorean theorm:
[tex]\text{Hypotenuse}^2=base^2+perpendicular^2[/tex][tex]\begin{gathered} \text{Hypotenuse}=w \\ \text{Base}=\text{ 24} \\ \text{perpendicular =24} \end{gathered}[/tex][tex]\begin{gathered} w^2=24^2+24^2 \\ w^2=576+576 \\ w^2=1152 \\ w=\sqrt[]{1152} \\ w=33.94 \end{gathered}[/tex]
(b)
For "h"
Perpendicular = h
Base = w/2
Hypotenuse = 24
Use pythagorean theorm
[tex]\begin{gathered} \text{Hypotenuse}^2=\text{Perpendicular}^2+\text{base}^2 \\ 24^2=h^2+(\frac{w}{2})^2 \\ 24^2=h^2+\frac{w^2}{4} \\ 576=h^2+\frac{1152}{4} \\ 576-288=h^2 \\ h^2=288 \\ h=\sqrt[]{288} \\ h=16.97 \end{gathered}[/tex]
So the height is 16.97
