First, let's look at the angle of 81° in the intersection point inside the circle.
We have a vertically opposite angle to this angle, in the left, and these angles are congruent, so this other angle is also 81°.
Then, looking at the small triangle with vertex E and D (and the intersection point), we can use the property that the sum of internal angles in a triangle is 180°:
[tex]\begin{gathered} E+D+81=180 \\ 30+D+81=180 \\ D=180-30-81 \\ D=69\degree \end{gathered}[/tex]
Now, looking at the angles A and D, they are incribed to the same arc in the circunference, so they are congruent.
Therefore we have ∠A = ∠D, so we have x = 69°, so the answer is the second option.
