We have a square
[tex]EF=10\sqrt[]{2}[/tex]
we can use the Pythagorean theorem in order to find y
[tex]3y+11=\sqrt[]{(10\sqrt[]{2})^2+(10\sqrt[]{2})^2}=20[/tex]
then we clear y
[tex]\begin{gathered} 3y+11=20 \\ 3y=20-11 \\ 3y=9 \\ y=\frac{9}{3} \\ y=3 \end{gathered}[/tex]
In order to find x, we need to remember the interior angles of a square are equals to 90° and the diagonals divided this angle into equal angles in other words the value is 45°
so we have the next equation
[tex]7x-25=45[/tex][tex]\begin{gathered} 7x=45+25 \\ 7x=70 \\ x=\frac{70}{7} \\ x=10 \end{gathered}[/tex]
the value of x=10
