We have the sequence of numbers: 123, 116, 109, 102, 95,... and the formula:
[tex]a_n=a_1+(n-1)d[/tex]We need to find the value of a1 and d. We can see that the first value is a1=123, and the next values just substract 7 units from the previous, so d=-7. And this answer the Part 1.
For Part 2 we need to find the explicit formula, which already did:
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ a_n=123-7\cdot(n-1) \end{gathered}[/tex]Part 3: Find the term of a100. We just need to replace n=100 in the formula above, so:
[tex]a_{100}=123-7\cdot(100-1)=123-693=-570[/tex]The sequence is arithmetic because,, as we already say above, the next value in the sequece add a constant from previuos value. In this case, the constant is d=-7, so the recursive formula is:
[tex]a_n=a_{n-1}-7[/tex]