So we have the following equation:
[tex]3x-6+x-2=180[/tex]And we have to re-write it. First we should group like terms. Two constant numbers are like terms just like two terms with the same power of x. Then we get:
[tex](3x+x)+(-6-2)=180[/tex]x is a common factor in the terms inside the first parenthesis so we can use the distributive property of the multiplication:
[tex](3x+x)=(3\cdot x+1\cdot x)=(3+1)\cdot x=4x[/tex]Then we get:
[tex]\begin{gathered} (3x+x)+(-6-2)=4x-8=180 \\ 4x-8=180 \end{gathered}[/tex]Then the answer to the first box is 4 and the answer to the second box is -8.