The total force applied to the roller can be obtained as,
[tex]\begin{gathered} F=(20\text{ kg-wt)(}\frac{9.8\text{ N}}{1\text{ kg-wt}}) \\ =196\text{ N} \end{gathered}[/tex]
The work done by the gardner can be given as,
[tex]W=Fd\cos \theta[/tex]
Substitute the known values,
[tex]\begin{gathered} W=(196N)(20m)(\frac{1\text{ J}}{1\text{ Nm}})cos70^{\circ} \\ =(3920\text{ J)(}0.342) \\ =1340.64\text{ J} \end{gathered}[/tex]
Thus, the work done by the gardener is 1340.64 J.
