Given:
the current through motor is
[tex]I=210\text{ A}[/tex]The potential of the battery is
[tex]V=12\text{ V}[/tex]The time is
[tex]t=10\text{ s}[/tex]Required: the energy delivered to the motor in 10 sec is?
Explanation:
first, we calculate the power delivered to the motor.
The power is given by
[tex]P=VI[/tex]Plugging all the values in the above relation, we get:
[tex]\begin{gathered} P=12\text{ V}\times210\text{ A} \\ P=2520\text{ watt} \end{gathered}[/tex]The energy delivered to the motor is given by
[tex]E=Pt[/tex]Plugging all the values in the above relation, we get:
[tex]\begin{gathered} E=2520\text{ w}\times10\text{ s} \\ E=25200\text{ J} \\ \end{gathered}[/tex]Thus, the energy delivered to the motor is 25200 J.
