Given data:
* The voltage of the given source is,
[tex]V=120\text{ Volts}[/tex]
* The current through the lamp is,
[tex]I=0.5\text{ A}[/tex]
Solution:
By the Ohm's law,
[tex]V=IR[/tex]
where R is the resistance of the lamp,
Substituting the known values,
[tex]\begin{gathered} 120=0.5\times R \\ R=\frac{120}{0.5} \\ R=240\text{ }\Omega \\ R=2.4\times10^2\text{ }\Omega \end{gathered}[/tex]
Thus, 3rd option is the correct answer.
