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a clay ball (0.65kg) is thrown at a wall and sticks. The speed of the ball before hitting the wall was 15 m/s. It took 45 miliseconds for the clay to come to a stop and make contact with the wall. What was the average force the wall exerted on the wall during the collision?

Respuesta :

In order to determine the average force the wall exerted on the ball, use the following formula:

[tex]F=\frac{\Delta p}{\Delta t}[/tex]

where

Δp: change in momentum

Δt: change in time = 45 ms = 0.045 s

F: force = ?

calculate the change in momentum as follow:

[tex]\Delta p=m\Delta v=(0.65kg)(15\frac{m}{s}-0\frac{m}{s})=9.75\text{ kg}\cdot\text{m/s}[/tex]

next, replace Δp and Δt into the formula for F:

[tex]F=\frac{9.75\text{ kgm/s}}{0.045s}=216.67N[/tex]

Hence, the average force exterded by the wall on the ball was approximately 216.67N

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