Given:
The total length of carriers A and B, T=4198 feet.
The difference in lengths of the carriers is, D=10 feet.
The length of football field, L=100 yards.
Let a be the length of carrier A and b be the length of carrier B. It is given that carrier A is longer than carrier B.
Hence, the expression for the difference in lengths of the carriers can be written as,
[tex]\begin{gathered} D=a-b \\ 10\text{ =a-b ----(1)} \end{gathered}[/tex]The total length of carriers A and B can be written as,
[tex]\begin{gathered} T=a+b \\ 4198=a+b\text{ ----(2)} \end{gathered}[/tex]Add equations (1) and (2) to find the value of a.
[tex]\begin{gathered} 2a=10+4198 \\ 2a=4208 \\ a=\frac{4208}{2} \\ a=2104\text{ f}eet \end{gathered}[/tex]We know, 1 yard=3 feet.
So, 1 feet=(1/3) yard
The length of carrier A in yards is,
[tex]a=2104\text{ f}eet\times\frac{\frac{1}{3}\text{yard}}{\text{ 1 fe}et}=\frac{2104}{3}\text{yards}[/tex]We know, the length of a football field is l=100 yards
Now, the ratio between a and l can be found as
[tex]\frac{a}{l}=\frac{\frac{2104}{3}\text{ yards}}{100\text{ yards}}\cong7.0[/tex]Hence, we can write
[tex]a=7.0\times l[/tex]Since l is the length of a football field, the length of carrier A is about 7.0 football fields.
