Hello!
The first step to solving this exercise is to draw the situation, look:
Now we can solve this exercise. Notice that we want to know the height that I called "X".
To find it, we must use the tangent of 20º, look:
[tex]\tan (20\degree)=\frac{opposite}{adjacent}[/tex][tex]\begin{gathered} \frac{0.364}{1}=\frac{60}{x} \\ \\ 0.364x=60 \\ x=\frac{60}{0.364} \\ \\ x\cong164.83 \end{gathered}[/tex]If each floor is 10 feet:
[tex]\frac{164.83}{10}=16.483\text{ floors}[/tex]If you have to approximate, you can say that it is 16.5 floors down.
