SOLUTION
We will be pairing the pumpkins as follows
AB, CD, EF and GH
For AB, we have
[tex]\begin{gathered} 16\frac{1}{2}\div5\frac{1}{2} \\ \frac{33}{2}\div\frac{11}{2} \\ \frac{33}{2}\times\frac{2}{11} \\ =\frac{33}{11} \\ =3 \end{gathered}[/tex]
Hence B is 3 times larger than A
For C and D, we have
[tex]\begin{gathered} 41\frac{1}{4}\div8\frac{1}{4} \\ \frac{165}{4}\div\frac{33}{4} \\ \frac{165}{4}\times\frac{4}{33} \\ =\frac{165}{33} \\ =5 \end{gathered}[/tex]
Hence D is 5 times larger than C
E and F, we have
[tex]\begin{gathered} 13\frac{3}{4}\div3 \\ \frac{55}{4}\div\frac{3}{1} \\ \frac{55}{4}\times\frac{1}{3} \\ =\frac{55}{12} \\ =4.5833333333 \\ =4.583 \end{gathered}[/tex]
Hence E is 4.583 times larger than F
And the last G and H, we have
[tex]\begin{gathered} 22\frac{3}{4}\div10\frac{1}{2} \\ \frac{91}{4}\div\frac{21}{2} \\ \frac{91}{4}\times\frac{2}{21} \\ =\frac{91}{21\times2} \\ =\frac{91}{42} \\ =2.167 \end{gathered}[/tex]
Hence G is 2.167 times larger than H
