FiThe radius, in inches, grows as a function of time in minutes according to:
[tex]r(t)=15\sqrt{t+2}[/tex]
We know that the area of a circle is given by:
[tex]A=\pi r^2[/tex]
Where r is the radius of the circle. Then, using r(t) in this equation:
[tex]\begin{gathered} A(t)=\pi\cdot\lbrack r(t)\rbrack^2=\pi\lbrack15\sqrt{t+2}\rbrack^2 \\ \\ \therefore A(t)=225\pi(t+2) \end{gathered}[/tex]
Finally, we evaluate this function for t = 2:
[tex]\begin{gathered} A(2)=225\pi(2+2)=225\pi(4) \\ \\ \therefore A(2)=900\pi\text{ in}^2 \end{gathered}[/tex]
