Solution
- The function given is
[tex]f(x)=\sin x[/tex]- We are asked to find
[tex]f^{\prime}(\frac{\pi}{3})[/tex]- The differentiation of the sine function gives:
[tex]f^{\prime}(x)=\frac{d}{dx}(\sin x)=\cos x[/tex]- Thus, we can solve the question by simply substituting π/3 into the function f'(x).
- That is,
[tex]\begin{gathered} f^{\prime}(x)=\cos x \\ put\text{ }x=\frac{\pi}{3} \\ \\ \therefore f^{\prime}(\frac{\pi}{3})=\cos\frac{\pi}{3}=\frac{1}{2} \end{gathered}[/tex]Final Answer
The answer is
[tex]f^{\prime}(\frac{\pi}{3})=\frac{1}{2}[/tex]