The objective function is:
[tex]F=2x+y[/tex]We need to find the shaded region where 4 inequalities overlap, then we need to graph the given inequalities:
[tex]\begin{gathered} 3x+5y\leq45 \\ 5y\leq-3x+45 \\ y\leq\frac{-3}{5}x+\frac{45}{5} \\ y\leq-\frac{3}{5}x+9 \end{gathered}[/tex]And the other one:
[tex]\begin{gathered} 2x+4y\leq32 \\ 4y\leq-2x+32 \\ y\leq\frac{-2x}{4}+\frac{32}{4} \\ y\leq-\frac{1}{2}x+8 \end{gathered}[/tex]And x>=0, y>=0
The graph is:
The coordinates of the shaded region are then:
(0,0), (0,8), (10,3) and (15,0)
To obtain the maximum value, let's evaluate the objective function in all the coordinates:
[tex]\begin{gathered} F(0,0)=2\times0+0=0+0=0 \\ F(0,8)=2\times0+8=0+8=8 \\ F(10,3)=2\times10+3=20+3=23 \\ F(15,0)=2\times15+0=30+0=30 \end{gathered}[/tex]Then, the maximum value is the largest value obtained, then it's 30 and it occurs at x=15 and y=0.
