ANSWER :
The answer is 42.79 years
EXPLANATION :
From the problem, we have the function :
[tex]A=A_oe^{0.015t}[/tex]
Solve for the value of t when A = 10,355 and Ao = 5,450
That will be :
[tex]\begin{gathered} 10355=5450e^{0.015t} \\ \frac{10355}{5450}=e^{0.015t} \\ 1.9=e^{0.015t} \\ \text{ Take the ln of both sides :} \\ \ln(1.9)=\ln(e^{0.015t}) \\ \ln(1.9)=0.015t \\ t=\frac{\ln(1.9)}{0.15} \\ t=42.79 \end{gathered}[/tex]
