7.60grams
The formula for calculating the molarity of a solution is expressed as;
[tex]molarity=\frac{mole}{volume}[/tex]Given the following parameters
molarity of solution = 0.250M
volume of sample = 200mL
Substitute to determine the mole of the solute
[tex]\begin{gathered} mole\text{ of }FeSO_4=molarity\times volume \\ mole\text{ of }FeSO_4=\frac{0.250mol}{L}\times0.2L \\ mole\text{ of }FeSO_4=0.05moles \end{gathered}[/tex]Determine the required mass of FesO4
[tex]\begin{gathered} Mass\text{ of FeSO}_4=mole\times molar\text{ mass} \\ Mass\text{ of FeSO}_4=0.05\times151.9 \\ Mass\text{ of FeSO}_4=7.595grams \\ Mass\text{ of FeSO}_4=7.60grams \end{gathered}[/tex]Hence the mass of FeSO4 is 7.60grams
