Given function is
[tex]f(x)=2x^2-5x+1[/tex]
Substitute the value of -2 in the equation we get
[tex]\begin{gathered} f(-2)=2(-2)^2-5\times-2+1_{} \\ =8+10+1 \\ =19 \end{gathered}[/tex]
Similarly find other values
[tex]\begin{gathered} f(-1)=2(-1)^2-5\times-1+1_{} \\ =2+5+1 \\ =8 \end{gathered}[/tex]
And then similarly f(1)=-2 and f(2)=-1 and f(0)=1
[tex]\begin{gathered} f(0)=2(0)^2-5\times0+1_{} \\ =0+0+1 \\ =1 \end{gathered}[/tex][tex]\begin{gathered} f(0)=2(0)^2-5\times0+1_{} \\ =0+0+1 \\ =1 \end{gathered}[/tex]
