Given:
Given a rectangle with coordinates A(-5, 6), B(3, 6), C(3, -1) and D(-5, -1).
Required: Area of rectangle ABCD
Explanation:
First, find the length and width of the rectangle.
[tex]\begin{gathered} \text{ Length, }DC=\sqrt{(-5-3)^2+(-1-(-1))^2} \\ =\sqrt{(-8)^2+0^2} \\ =8 \\ \text{ Width, }BC=\sqrt{(3-3)^2+(6-(-1))^2} \\ =\sqrt{0^2+7^2} \\ =7 \end{gathered}[/tex]
The are of the rectangle is
[tex]\begin{gathered} A=\text{Length}\times\text{Width} \\ =8\times7 \\ =56 \end{gathered}[/tex]
Option C is correct.
Final Answer: Rectangle ABCD has area 56 square units.
