Given:
Given the equation of the circle
[tex](x+3)^2+(y-4)^2=16[/tex]Required: Radius and center of the circle
Explanation:
The standard form of an equation of a circle is of the form
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h, k) is the center and r is the radius.
Re-write the given equation of circle in standard form.
[tex](x-(-3))^2+(y-4)^2=4^2[/tex]Comparing with the standard form,
center: (h, k) = (-3, 4)
Radius: r = 4
Final Answer: Center = (-3, 4) and radius = 4.
