Given,
The charge passed through the resistor, q=1.833 C
The time, t=1,538 s
The electric current can be defined as the time rate of flow of charge. Thus the electric current that passes through the resistor is given by,
[tex]I=\frac{q}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} I=\frac{1.833}{1538} \\ =1.191807\times10^{-3}\text{ A} \\ =1.191807\text{ mA} \end{gathered}[/tex]Thus the current of the circuit is 1.191807 mA.
