Raina, Kevin, and Eric have a total of $66 in their wallets. Kevin has 3 times what Eric has. Raina has $9 less than Eric. How much does each have?

Respuesta :

In order to determine the amount of money Rain, Kevin and Eric have, write the given situation as an algebraic equation.

If x is the money of Raina, y the money of Kevin and z the money of Eric, you have, based on the given problem, the following equations:

x + y + z = 66 All of them have a total of $66

y = 3z Kevin has 3 times what Eric has

x = z - 9 Raina has $9 less than Eric

Replace the expressions for x and y into the first equation and solve for z, as follow:

(z - 9) + (3z) + z = 66

z - 9 + 3z + z = 66

3z = 66 + 9

3z = 75

z = 75/3

z = 25

Next, replace the previous value of z into the expressions for x and y:

y = 3(25)

y = 75

x = 25 - 9

x = 16

Hence, the amount of money each of them has is:

Raina: $16

Kevin: $75

Eric: $75