Respuesta :
SOLUTION:
Step 1:
In this question, we are given the following:
A block of ice is in the shape of a cube with side lengths of 1.8 inches.
The ice has a density of 876 kg per cubic inch.
Find the mass of the block of ice to the nearest tenth of a kg.
Step 2:
The details of the solution are as follows:
Recall that:
[tex]\begin{gathered} Density\text{ = }\frac{Mass}{Volume} \\ where\text{ Volume of the cube = length x length x length} \\ Volume\text{ of the cube = 1. 8 x 1. 8 x 1. 8 = 5.832 inches}^3 \end{gathered}[/tex][tex]Density\text{ = 876 kg per cubic inch}[/tex][tex]\begin{gathered} Therfore,\text{ mass of of the block of ice = Density x volume} \\ Mass\text{ of the bolock of ice = 876 x 5.832 = 5108. 832 kg}\approx\text{ 5108.8 kg} \\ (\text{ to the nearest tenth of a kg \rparen} \end{gathered}[/tex]CONCLUSION:
The mass of the block of ice to the nearest tenth of a kg =
[tex]5108.8\text{ kg }[/tex]
