SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given equation
[tex]18x-9y+3z=18[/tex]To get the intercepts, we pick a point and equate the others to zero and then solve for the point.
STEP 2: Get the values of x when y and z are zeroes
[tex]\begin{gathered} 18x-9y+3z=1,z) \\ 18x-9(0)+3(0)=18 \\ 18x-0+0=18,18x=18 \\ Divide\text{ both sides by 18} \\ \frac{18x}{18}=\frac{18}{18} \\ x=1 \\ (x,y,z)\Rightarrow(1,0,0) \end{gathered}[/tex]STEP 3: Get the values of y when x and z are zeroes
[tex]\begin{gathered} 18x-9y+3z=18_{} \\ \text{Let x and z be 0} \\ 18(0)-9y+3(0)=18 \\ 0-9y+0=18 \\ -9y=18 \\ Divide\text{ both sides by -9} \\ \frac{-9y}{-9}=\frac{18}{-9} \\ y=-2 \\ (x,y,z)\Rightarrow(0,-2,0) \end{gathered}[/tex]STEP 4: Get the value of z when x and y are zeroes
[tex]\begin{gathered} 18x-9y+3z=18_{} \\ \text{Let x and y be 0} \\ 18(0)-9(0)+3z=18 \\ 3z=18 \\ Divide\text{ both sides by 3} \\ \frac{3z}{3}=\frac{18}{3} \\ z=6 \\ (x,y,z)\Rightarrow(0,0,6) \end{gathered}[/tex]Hence, the intercepts are:
[tex](1,0,0),(0,-2,0),(0,0,6)[/tex]