For Monday morning's staff meeting, Jim bought 3 bags of bagels and 3 packages of cream cheese and paid $16.50 (excluding sales tax).For Friday's meeting, he bought 5 bags of bagels and 2 packages of cream cheese and paid $22.25 (again, excluding sales tax). How much dobags of bagels and packages of cream cheese cost?

For Monday mornings staff meeting Jim bought 3 bags of bagels and 3 packages of cream cheese and paid 1650 excluding sales taxFor Fridays meeting he bought 5 ba class=
For Monday mornings staff meeting Jim bought 3 bags of bagels and 3 packages of cream cheese and paid 1650 excluding sales taxFor Fridays meeting he bought 5 ba class=

Respuesta :

Answer:

Explanation:

Let the price of one bag of bagel = b

Let the price of one package of cream cheese = c

3 bags of bagels and 3 packages of cream cheese costs $16.50.

[tex]3b+3c=16.50\cdots(1)[/tex]

5 bags of bagels and 2 packages of cream cheese costs $22.25.

[tex]5b+2c=22.25\cdots(2)[/tex]

Thus, we derive a system of two linear equations which we then solve for b and c.

[tex]\begin{gathered} 3b+3c=16.50\operatorname{\cdots}(1) \\ 5b+2c=22.25\operatorname{\cdots}(2) \end{gathered}[/tex]

Multiply equation 1 by 5 and equation 2 by 3.

[tex]\begin{gathered} 15b+15c=82.5 \\ 15b+6c=66.75 \end{gathered}[/tex]

Subtract to eliminate b.

[tex]9c=15.75[/tex]

Divide both sides by 9:

[tex]\begin{gathered} \frac{9c}{9}=\frac{15.75}{9} \\ c=1.75 \end{gathered}[/tex]

Next, substitute c=1.75 into equation 1.

[tex]\begin{gathered} 3b+3c=16.50 \\ 3b+3(1.75)=16.50 \\ 3b=16.50-3(1.75)=11.25 \\ b=\frac{11.25}{3}=3.75 \end{gathered}[/tex]

The price per bag of bagel is $3.75 and the price per package of cream cheese is $1.75.