Explanation:
Remember that colorblindness is an X-linked recessive disorder. Now, let us denote by "a" the recessive (affected) allele and by "A" the dominant (normal) allele.
Now, consider the following pedigree chart:
Suppose individuals 21 and 22 have only male biological children. First, notice that individual 21 is a normal female (no carrier). This means that her genotype:
[tex]X_AX_A[/tex]
On the other side, individual 22 presents the affected allele. Since individual 22 is a man, this means that his genotype for the colorblindness would be:
[tex]X_aY[/tex]
thus, the Punnett square of the crossing of these two individuals would be:
Now, according to the problem, individuals 21 and 22 have only male biological children. Then, according to the above Punnett square, we can infer that the percent of children (male biological children) that are colorblind is:
0%
we can conclude that the correct answer is:
Answer:
The percent of children (male biological children) that are colorblind is:
0%
