Respuesta :

[tex]\begin{gathered} \angle ABC\text{ and }\angle CAD\text{ are supplementary angles } \\ \text{Therefore,} \\ \angle ABC+\angle CAD=180\text{ degree} \\ \angle ABC=3x-7 \\ \angle CAD=2x+32 \\ 3x-7+2x+32=180 \\ 5x+25=180 \\ 5x=180-25 \\ 5x=155 \\ x=\frac{155}{5} \\ x=31 \end{gathered}[/tex][tex]\begin{gathered} \text{Therefore,} \\ \angle BAD=2x+32 \\ \angle BAD=2(31)+32 \\ \angle BAD=62+32 \\ \angle BAD=94\text{ degrees} \end{gathered}[/tex]

D.