To answer this question, we need to use the formula for the volume of a cone, as follows:
[tex]V_{\text{cone}}=\frac{1}{3}\cdot\pi\cdot r^2\cdot h[/tex]
We have from the graph that the diameter of the cone is equal to 20 inches. The radius is half of this value. Then, we have that the radius is equal to 20 in/ 2 = 10 inches.
Now, we can apply the formula for the volume of this cone, because we have:
• r = 10 inches (the radius of the cone)
,
• h = 6 inches (the height of the cone)
Then, we have:
[tex]V_{\text{cone}}=\frac{1}{3}\cdot\pi\cdot(10in)^2\cdot6in=\frac{1}{3}\cdot\pi\cdot100in^2\cdot6in=\frac{1}{3}\cdot\pi\cdot600in^3[/tex]
Therefore
[tex]V_{\text{cone}}=\frac{600in^3}{3}\cdot\pi=200in^3\cdot\pi[/tex]
If we approximate pi to 3.1416, we have that the volume of the cone is, approximately:
[tex]V_{\text{cone}}=200in^3\cdot\pi=628.32in^3[/tex]
