Answer:
D. 0.32
Explanation:
The probability of a person driving while intoxicated or having a car accident can be calculated as:
[tex]P=P(\text{Intoxicated)}+P(\text{ Accident) - P(Intoxicated and Accident)}[/tex]So, replacing P(Intoxicated) = 0.28, P(Accident) = 0.08 and P(Intoxicated and Accident) = 0.04, we get
[tex]\begin{gathered} P=0.28+0.08-0.04 \\ P=0.32 \end{gathered}[/tex]Therefore, the answer is
D. 0.32
