We have the following:
[tex]\begin{gathered} -7x-2y=-13 \\ x-2y=11 \end{gathered}[/tex]solving by substitution:
[tex]\begin{gathered} x-2y=11\Rightarrow x=11+2y \\ \text{replacing} \\ -7\cdot(11+2y)-2y=-13 \\ -77-14y-2y=-13 \\ -16y=-13+77 \\ y=\frac{64}{-16} \\ y=-4 \end{gathered}[/tex]now, for x
[tex]\begin{gathered} x=11+2\cdot-4 \\ x=11-8 \\ x=3 \end{gathered}[/tex]The solution is
[tex](3,-4)[/tex]